To keep a station stationary above a point on Earths surface takes a force of:
F = mrω²
where r is the radius of the forced orbit, say 1000 km plus the Earth radius of 6400 km = 7400 km, and ω is the angular velocity 2π/86164s ≈ 0.000073 s⁻¹.
So F = mrω² ≈ m × 7400000 × 0.000073² ≈ m × 0.039 m/s² which is next to nothing. The problem is that gravity provides GM/r² ≈ 7.279 m/s² at that height.
So to stay in that forced orbit we need to accelerate at 7.279 - 0.039 ≈ 7.240 m/s² ≈ 0.74 g.
(Please check my calculations, I'm doing this with the help of wiki.)
To stay wherever we want over the planet we need a large fraction of 1 g, so almost a 1 g drive. 0.1 g will not make many forced orbits possible.