TL, stats of clockwork?

[TheEngineer]

Hi !

The perhaps easiest approximation to that in to use per volume elastic energy calculation.
You just need an E or Young module and a strain factor for that.

So, energy per m3 is

E per m^3 = 0,5 * E-module * relative strain^2

Using steel stats e-module is around 200000 MN/m2.
If extended/compressed by 10 %, that would result in 0,5*200000MN/m^2*0,1^2 = 1000 MJ/m^3.

So, this theoretical "stressed block" could release 1 MW for about 1000 seconds, before it needs to be re-stressed.

Nanotubes E-modules reach much higher values (factor 5 to 10(?) compared to steel), so energy densitiy increases considerablely.

Its a very rough sketch, but perhaps permits to get an impression about energy densities.

regards,

Mert

 

[archhealer]

Ahh... so perhaps much like batteries, we'd have to have different stats for clockworks at different tech levels. I imagine something along the lines of weights and rope at TL1, steel by TL4 at the latest... What after that? Alloys? Carbon fiber? Then nanotubes? I don't imagine more than three or four steps would be practical.