I'm better at following examples.
no problem. figuring out how to explain this properly is valuable experience.
no, the ships move in pixels. 1 turn of acceleration at 1G will result in a vector (a movement in a direction per turn) of 1 pixel per turn in that direction.
I've updated the graphic and tracker above to show the sdb accelerating at 6G straight at the warship for 3 turns, to illustrate it's movement.
at the start of turn 1 the sdb is at (x,y)(120,300) and is 4.0 LS away from the warship. it has a vector of (xv,yv)(000,000). it accelerates at 6G directly towards the warship, (xd,yd)(006,000). at the end of turn 1 the sdb has moved 3 pixels to (x,y)(123,300).
at the start of turn 2 the sdb is at (x,y)(123,300) and is 3.9 LS away from the warship. it has a vector of (xv,yv)(006,000). it accelerates at 6G directly towards the warship, (xd,yd)(006,000). at the end of turn 2 the sdb has moved 9 pixels to (x,y)(132,300).
at the start of turn 3 the sdb is at (x,y)(132,300) and is 3.6 LS away from the warship. it has a vector of (xv,yv)(012,000). it accelerates at 6G directly towards the warship, (xd,yd)(006,000). at the end of turn 3 the sdb has moved 15 pixels to (x,y)(147,300).
at the start of turn 4 the sdb is at (x,y)(147,300) and is 3.1 LS away from the warship. it has a vector of (xv,yv)(018,000).