Not stopped, but rather slowed its rotation rate. Otherwise, what will be its effective surface gravity when you compare its natural gravity due to mass combined with its centrifugal force due to rotation?
Also, unlike a sphere gravity will not be directed uniformly towards the "interior" of the torus-mass either. The interior-facing surface of the torus will be at a different gravitational potential than the outer-facing surface (and so will the "upper" and "lower" surfaces that are perpendicular to the interior and exterior surfaces). That will make for interesting atmospheric dynamics, presuming it has one. Gravity for a toroid from its center of rotation to its outer-surface can be roughly approximated as directed toward the center-point along the axis of rotation, and will fall off from the center point as 1/R (not 1/R
2). The magnitude of the gravity will be based on the amount of mass enclosed by a notional cylinder symmetric about the axis of rotation, out to a radius "r" defined by the point at which you wish to measure it. This likely means that the interior-facing surface of rotation will be in microgravity; full gravity will be encountered along the outer-facing surface of rotation.
Discussion:
https://www.reddit.com/r/askscience/comments/6isvfm/physics_how_does_gravity_work_on_a_torus_world/
Ringworlds are not naturally formed, but are artificially constructed of super/ultra-dense materials, and use rotation to create a habitat along the inner surface with "gravity" due to centrifugal force. The ringworld needs the ultra-dense construction material in order to withstand the stresses associated with the rotation of an object of that size.
I am of course assuming that you are envisioning this world as a "rocky/solid" world with the outer-surface of the torus to live upon, and not either a toroidal "gas-giant" or a solid torus with habitats bored into the interior (please correct me if my presupposition is incorrect).