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Striker Book 3 CBM Burst Size questions

snrdg082102

SOC-14 1K
Morning again all,

Striker Book 3 DS 2 L 5 CBM, page 15, doesn't mention the need to calculate a burst size which is clearly shown in the self-propelled autocannon example on Striker Book 3 page 30.

Striker Book 1 Rule 24 on page 40 does indicate that the CBM round has a burst size 4 x that specified for the weapon.

This has led to some questions:

1. Does the HE burst size start with the bore size of 4 or 8 cm?
2. Do I calculate burst size based on the weapon's bore size?
3. Do I use the HE TL modifier process to determine the burst size?
4. If the HE TL modifier is used would I use the HE TL or CBM TL to determine how many rows to move down?
5. I need to count down 2 rows and the burst size is multiplied by 4 for a CBM mortar?

Here is what I think happens using the example from Book 3 page 30.
The TL 9 8 cm triple barrel low velocity autocannon the following characteristics: Contact pen./Burst Size/Frag. pen/hit DM: 21/8/7/+1.

The CBM ammunition Fragmentation Pen value is determined by using the contact penetration of 4 cm HE round. The HE round contact is determined by counting down 1 row for every 2 levels (or fraction thereof) above TL 6. At TL 9 there are 3 levels between the base TL 6, which I hope means, to count down 2 rows. A 4 cm HE round has a contact pen value of 5 and counting down 2 rows indicates that the TL 9 CBM round has a frag pen of 7.

I'm guessing that the CBM burst size is calculated by using the HE round burst size values. Reverse engineering of the autocannons burst size per Book 1 Rule 24 the HE burst size is 8/4 = 2.

Cross referencing the HE Pen column back to bore size returns the value of 8 cm. If my reverse engineering is correct then the starting point is 8 cm instead of 4 cm that determines frag pen.

Question 1. Does the HE burst size start with the bore size of 4 or 8 cm?

The answer for question 1 appears to be 8 cm since the burst size value of 2 starts there and goes downs to a 12 cm bore.

Question 2. Do I calculate burst size based on the weapon's bore size?

If I'm on the right track a 13 cm CBM round burst size is 3 x 4 = 12 is the answer to my second question.

Questions 3, 4, and 5 of using the HE/CBM TL as a modifier and mortar modifier matters only if burst size is determined by bore size.

A TL 9 12 cm CBM mortar round burst size starts at 2 moves down 1 or 2 rows both of which results in a burst size of 3 and then is multiplied by 4 for being a CBM round resulting in a final burst size of 12.

Did I answer my own questions or am I out to lunch?
 
Morning again all,

Striker Book 3 DS 2 L 5 CBM, page 15, doesn't mention the need to calculate a burst size which is clearly shown in the self-propelled autocannon example on Striker Book 3 page 30.

Striker Book 1 Rule 24 on page 40 does indicate that the CBM round has a burst size 4 x that specified for the weapon.

This has led to some questions:

1. Does the HE burst size start with the bore size of 4 or 8 cm?
2. Do I calculate burst size based on the weapon's bore size?
3. Do I use the HE TL modifier process to determine the burst size?
4. If the HE TL modifier is used would I use the HE TL or CBM TL to determine how many rows to move down?
5. I need to count down 2 rows and the burst size is multiplied by 4 for a CBM mortar?

Here is what I think happens using the example from Book 3 page 30.
The TL 9 8 cm triple barrel low velocity autocannon the following characteristics: Contact pen./Burst Size/Frag. pen/hit DM: 21/8/7/+1.

The CBM ammunition Fragmentation Pen value is determined by using the contact penetration of 4 cm HE round. The HE round contact is determined by counting down 1 row for every 2 levels (or fraction thereof) above TL 6. At TL 9 there are 3 levels between the base TL 6, which I hope means, to count down 2 rows. A 4 cm HE round has a contact pen value of 5 and counting down 2 rows indicates that the TL 9 CBM round has a frag pen of 7.

I'm guessing that the CBM burst size is calculated by using the HE round burst size values. Reverse engineering of the autocannons burst size per Book 1 Rule 24 the HE burst size is 8/4 = 2.

Cross referencing the HE Pen column back to bore size returns the value of 8 cm. If my reverse engineering is correct then the starting point is 8 cm instead of 4 cm that determines frag pen.

Question 1. Does the HE burst size start with the bore size of 4 or 8 cm?

The answer for question 1 appears to be 8 cm since the burst size value of 2 starts there and goes downs to a 12 cm bore.

Question 2. Do I calculate burst size based on the weapon's bore size?

If I'm on the right track a 13 cm CBM round burst size is 3 x 4 = 12 is the answer to my second question.

Questions 3, 4, and 5 of using the HE/CBM TL as a modifier and mortar modifier matters only if burst size is determined by bore size.

A TL 9 12 cm CBM mortar round burst size starts at 2 moves down 1 or 2 rows both of which results in a burst size of 3 and then is multiplied by 4 for being a CBM round resulting in a final burst size of 12.

Did I answer my own questions or am I out to lunch?

Looks right
 
Afternoon all,

The design example for Design Sequence 2 doesn't provide any information on determining the burst size for a TL 9 11 cm medium velocity CBM round. To verify I'm on the right track I'm going to, hopefully, work out the burst size once using the HE TL and a second time using the CBM TL.

The HE penetration characteristics are modified by counting down 1 row for each 2 tech levels above 6, or fraction thereof. Book 3 L - Ammunition - 1. HE page 15

The CBM rounds burst size is 4 times the size of the one specified for the bore size. Book 1 Rule 24 page 40

A. HE TL
A 11 cm round has a burst size of 2 per the CPR gun table. At TL 9 the HE TL modifier, I hope, is 2, Counting down 2 rows changes the burst size from 2 to 3. Multiplying 3 by 4 the final burst size is 12.

B. CBM TL
A 11 cm round has a burst size of 2 per the CPR gun table. Using the CBM TL of 7 instead of the HE TL of 6 at TL 9 the CBM TL modifier is 1, counting down 1 row the burst size is still 2. Multiplying 2 by 4 the final burst size is 8.

C. No modifier used.
Determine the burst size for the bore size on the CPR Gun table and multiply by 4. A 11 cm round has a HE burst size of 2 x 4 = a CBM burst size of 8.

Which method A, B, or C is the correct one to use?

I'm leaning toward A, but I'm not sure since the TL 9 8-cm triple barrel autocannon example on Book 3 page 30 could could use any one of the three.
 
Morning Carlobrand for the second time,

Me, I'd say A - but I don't think the rules are specific on that point.

Two votes for A which is using the HE TL to figure out the modifier for determining a CBM round burst size.

Without looking at the autocannon on page 30 of Book 3 I didn't realized a CBM round has a burst size. Without help I'd probably still be searching for Book 1 Rule 24 on page 40 that states the burst size is 4 x the indicated size for that bore size.

My intention was to go through all the design sequences before submitting possible errata and now I'm considering posting errata for each sequence after I've reviewed the section a couple of times.

Thanks for the vote for A.
 
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