RandyT0001
SOC-13
I was thinking (yes, I get these light bulbs in my head, most die of loneliness) about a new variation on the ol' jump drive. In the OTU a ship with a jump drive 6 takes a week, 168 hours +/- 10% to make a jump, even a jump of one hex (or parsec). Now suppose that the time a jump 6 drive takes to make that jump of one hex (one parsec) takes only 1/6 the normal time, one day, four hours +/- 10%. To make a jump of three parsecs, a jump 6 drive would take half the normal time, 3.5 days +/-10%.
So what you do is divide the number of parsec hexes actually jumped by the jump drive number, for example, 1/6 = 0.16667. That factor multiplied by 168 hours gives the new travel time (still with the 10% variation). So jumping two parsecs with a jump 5 drive takes 0.4*168=67.2 hours or 2 days, 19 hours, 12 minutes (+/- 10%).
Any thoughts, comments?
So what you do is divide the number of parsec hexes actually jumped by the jump drive number, for example, 1/6 = 0.16667. That factor multiplied by 168 hours gives the new travel time (still with the 10% variation). So jumping two parsecs with a jump 5 drive takes 0.4*168=67.2 hours or 2 days, 19 hours, 12 minutes (+/- 10%).
Any thoughts, comments?