I crunched it a few decades ago in college and came up with something in the neighborhood of 0.17c (and around 1 million Kelvins), so your calculation back in 2003 has always seemed to me to be, if anything, slightly on the conservative side.
:alpha:
So if we assume each maneuver drive can operate for 4 weeks, with 2 weeks of acceleration and 2 weeks to decelerate we get the following maximum velocities:
Maneuver 1 = 2% of the speed of light
Maneuver 2 = 4% of the speed of light
Maneuver 3 = 6% of the speed of light
Maneuver 4 = 8% of the speed of light
Maneuver 5 = 10% of the speed of light
Maneuver 6 = 12% of the speed of light
Where in order to operate for 4 weeks
Maneuver 1 requires 10% of the hull volume to be fuel
Maneuver 2 requires 20% of the hull volume to be fuel
Maneuver 3 requires 30% of the hull volume to be fuel
Maneuver 4 requires 40% of the hull volume to be fuel
Maneuver 5 requires 50% of the hull volume to be fuel
Maneuver 6 requires 60% of the hull volume to be fuel
Under this system there is only one kind of jump drive, you charge its capacitor for 2 weeks, and the highest speed your Starship attains determines what kind of jump your Starship makes, if you get to 2% of the speed of light you can do a Jump-1, if you get to 4% of the speed of light you can do a jump-2. To put it another way, every percentage point of the speed of light that you can reach, you can jump half a parsec, this doesn't cap out at jump-6 either, the limiting factor is how fast your Starship can go. If you are desperate to send a message, you can accelerate a maneuver-6 starship to 24%, by using all of its fuel of the speed of light and do a jump-12. If the ship is manned, you can use staging to achieve this, essentially have a larger starship carry a smaller Starship, and you lose the larger Starship, and use the fully fueled smaller Starship to save the crew, they decelerate for 4 weeks to go from 24% of the speed of light to 0% of the speed of light.