So I think we need a walkthru dedicated to building drives from the tables -and- building starships "backwards" (sum up the payload first, then sum up all the percentage-based elements, turn the math grinder one crank, and out pops a ship).
The issue I ran into is that those percentages can vary by total hull size. For example, J-4 in 200 ton hull is 12.5%, in 400 ton hull is 11.25%, and in 800 ton hull is 10.6% -- the bigger the hull, the less space the drive uses as a percentage.
A bit of handling should fix this problem. The formulas on page 337 show you how:
J - Jump Drive
Jump Volume = ( Hv x Jn / 200 ) x 5 + 5;
round up the result in parenthesis before multiplying by 5.
Hv = hull volume.
Jn = jump number.
Examples
Jump-4, from the table:
200t hull = D drive = 20t + 5t
400t hull = H drive = 40t + 5t
800t hull = R drive = 80t + 5t
Jump-4, from formula:
200t hull: J-drive vol = (H x Jn / 200) x 5 + 5 = (200 x 4 / 200) x 5 + 5 = 25t
400t hull: J-drive vol = (400 x 4 / 200) x 5 + 5 = 45t
800t hull: J-drive vol = (800 x 4 / 200) x 5 + 5 = 85t
Shift the 5 tons of overhead out of 'drives' and into 'payload', and you're good.
(Note that this means that if you have a jump drive, maneuver drive, and power plant, then your payload increases by 5 tons. Why? Because that's the total overhead of all three: Jump drives are +5, Maneuver drive is -1, and Power plant is +1. Except of course when you're using Maneuver Drive A, in which case your total drive overhead is 6 tons).
Now the Antimatter plant has errata logged against it (the formula on page 337 is assumed to be correct, and the table is assumed to be incorrect), and M-drive A hits that minimum volume requirement. But the other drives all play nice.