Hop drive misjumps

[dalthor]

IMTU the Varans are a major race, having developed Jump independently about 2000 years ago. They haven't officially contacted the Imperium at this time.

Both the Varans and Imperium have the ability to produce Hop-1 drives as prototype or early versions.

During testing of a hop drive, would a misjump consist of 1-36 hexes TIMES TEN, giving a range of 10 - 360 hexes? IMTU that is the case, since hop is ten times the distance of jump.

I've been setting up my own sector using the Mikhail sector (see http://wiki.travellerrpg.com/Mikhail_Sector ). Thanks to Joshua Bell, the data is also on the travellermap.com site, at (3,5)

This is also how the Varans and the Imperium are going to "meet" initially. I'm working on a first-contact campaign, and a large misjump is integral to the story. See more on the wiki page...

Anyway, again, is it logical that a Hop misjump is 1-36 * 10 hexes? YMMV, but I hadn't found anything official.

Dalthor

 

[SpaceBadger]

I'm afraid I can't comment on your question about Hop misjumps (although your suggestion seems logical), but just wanted to say that your Wiki page on the Varan was very interesting. Are you planning to run a PbP campaign in Varan space? If so, I look forward to reading it.

 

[Reban]

Check out page 374 under Random Exit where it says "For the fantastic drives, the distance to the location is multiplied by the Drive Multiplier."

The Multiplier for a Hop Drive is ^1 so essentially yes you're right to multiply by 10 hexes.

[Edit] Assuming a Hop-1 Drive the calculation for a misjump will be:

((1+1D)= nHexes)x10


[EDIT2] Hang on I think I have that slightly wrong. The result is in Dice not hexes. So its

((1+1D)=nDice)x10= nHexes

So for a Hop-1 on a throw of 3 on 1D:

((1+3)=nDice)x10
((4)=4D)x10

So that will be 40 to 240 Hexes distance traveled in a Hop-1 Misjump.

 

[dalthor]

The info on page 374 regarding the random exit point isn't really clear - the example doesn't seem to match what the text is showing.

The "Dice = jump number times 1D" seems straightforward - roll one die, multiply by the jump number, and roll that number of dice for distance. The example seems to indicate an initial die roll of 3. I'd therefore expect the example to have a final roll of 3d6 times jump. The final word in the example should be "dice" instead of "hexes" to match the formula given.

I'm thinking this should be an errata question...I didn't find an answer in the current errata.

Dalthor

 

[dalthor]

I hadn't really contemplated a PbP, at least not starting in Varan space. I'll think about that, tho.

Glad u liked the write-up, still some work to do before the campaign starts, but for now there is enough to get it going.

Dalthor

 

[rclauson]

Without seeing any official errata on it, my guess had been that the word "Dice" on page 374 was the error and "hexes" in the example was correct.

That would make the misjump distances for these examples:
Jump1 = 1d6 parsecs
Jump6 = 6d6 parsecs
Hop1 = 10 x 1d6 parsecs
Skip4 = 100 x 4d6 parsecs