CT Only: Typical travel times chart in LBB 2

[Olschoolgamer]

I know this is probably somewhere else and I accept any pummeling I get but.

On page 10 of the Starships book for CT the numbers for the 1,000 Kilometers appear to be in the 10,000 kilometers row.

I wanted to make sure I was calculating everything correctly. The constants are meters, seconds and Gs.

So converting the 1,000 kilometers to meters gives 1,000,000 meters.

Using this number I calculated the seconds for the trip with a turn around mid point and found the results match the 10,000 kilometer row.

Can anyone point out what is probably a simple miscalculation on my part?

 

[aramis]

Several possibilities

There are two possible situations

D=0.5AT² V=AT²	or	or D=2*0.5A(T/2)² V=0

[tc=3]G=9.81m/s²[/tc]

and one constant that is not of need a constant

G=9.80665

G=9.81

G=10

So working 1000km, both situations, to find the answer closest to 633...

1,000,000=0.5×9.81×T² 2×1,000,000={2×0.5}×9.81×T² 2,000,000=9.81×T² 2,000,000/9.81={9.81/9.81}×T² 203873.5983690112=T² √203873.5983690112=√T² 451.5236=T		D=2×0.5A(T/2)² D={2*0.5}9.81(T/2)² 1,000,000=9.81(T/2)² 1,000,000/9.81={9.81/9.81}(T/2)² 101936.7991845056=(T/2)² √101936.7991845056=√(T/2)² 319.27542840705047=T/2 2×319.27542840705047=T×{2/2} 638.5508568141009=T
1,000,000=0.5×10×T² 2×1,000,000={2×0.5}×10×T² 2,000,000/10={10/10}×T² 200,000=T² √200,000=√T² 447.21359549995793=T		D=2×0.5A(T/2)² 1,000,000={2×0.5}×10(T/2)² 1,000,000/10={10/10}(T/2)² 100,000=(T/2)² √100,000=√(T/2)² 316.22776601683796=T/2 2×316.22776601683796=T{2/2} 632.4555320336759=T

[tc=3]G=9.81m/s²[/tc] [tc=3]G=10m/s²[/tc]

Bottom right looks close enough, given the whole table is rounded to or truncated to seconds. Looks like rounded up.
Traveller G=10m/s²
And you need to use the double half-distance version for coming to a stop.

Double checking 10 & full stop for 1,000,000 km.

D=2×0.5×A(T/2)² 1,000,000,000=2×0.5×10(T/2)² 1,000,000,000/10={2×0.5}×{10/10}(T/2)² 100,000,000=(T/2)² √100,000,000=√(T/2)² 10,000=T/2 10,000×2=T{×2/2} 20,000=T (Seconds) 20,000/60 = T (Minutes)

333.3333333333333 = T Minutes

Cross check confirms.

 

[AnotherDilbert]

D = At²/2, where A = 10 m/s² (I'm lazy).

Since we accelerate to the midpoint, and then decelerate to a full stop we use half the distance, and then double the time.

1 000 km = 1 000 000 m, half is 500 000 m.

500 000 m = 10 × t² / 2 => t² = 500 000 × 2 / 10 = 100 000 =>
t = √100000 ≈ 316 s

So the total time is 2 × 316 = 632 s, just as the table says?


Sorry Aramis, you already said that, but you used so many calculations and tables that I did not understand you.

The constants are meters, seconds and Gs.

No:

The variables are time (T) in seconds, distance (D) in meters, and acceleration (A) in meters/second².

to get meters/second² from Gs he must multiply by 10 (1G=10 meters/second²).

 

[Olschoolgamer]

The Gs are what I am missing, I didn't multiple by 10. I read the paragraph again and see where it says that.
I suppose one could just make a chart with all the most common distances like 100 world diameters for the jump distance.
Thanx.

 

[jcrocker]

If you have MegaTraveller, it's in the Referee's Companion book, page 21. Big full page table.

 

[ShawnDriscoll]

If you have MegaTraveller, it's in the Referee's Companion book, page 21. Big full page table.

You mean have all of MegaTraveller.

 

[aramis]

Sorry Aramis, you already said that, but you used so many calculations and tables that I did not understand you.

All I did was show each step, in exactly the same manner I always do.