generate irregular orbit with Decimal Orbits table

[rich4421972]

For my question , I am referring to section 6 of the World Ranges Table chapter (pg 44 of the BBB, or page 23 of "Basic Information" on the CD-ROM version of the Core Rules)

I would like to generate an irregular decimal orbit between the regular orbits, 10 and 12, of a star system using the T5 decimal orbit table. I rolled a -3 flux( 3-6 on the flux dice) for the desired orbit

With a flux value of -3, I am assuming that my irregular orbit is at its closest distance (65.7 AU) at orbit 10.3 and at its farthest distance (200.3 AU) at orbit 11.3. Am I doing this right?

I started at 10 Orbit and traced my finger until I was directly under -3 Flux. The value is given as 65.7 AU. I assume that this was the closest distance to the star itself.

In a similar way (using Flux +3), I used orbit 11 and got the value of 200.3 AU Thus, I think that I would denote this irregular orbit :

O=11.3 [10.7 to 11.3]

I think that my mistake is in the use of a positive/negative flux value (-3/+3). Could anybody tell me if I made a mistake with flux or any other aspect?
Thank you so much for your input.

 

[andycowley]

rich4421972,

I tried to follow your method but get a different answer .... I 'think' you may be off by one vertical row in the table... Here's what I get ...

You want an Orbit between 10 and 12 .... so start on the Orbit = 11 row (see orbits on right side of page 44 table) ...

You roll flux = -3 .... this gives you a closest orbital approach of 10.7 (130AU)

You then take flux +3 ... this gives you a farthest orbital distance of 11.3 (200AU) ....

So your eccentric orbital descriptor is; O=11 (from 10.7 to 11.3)

 

[rich4421972]

Thank you so much. I knew I was off by something.

I didn't see that I needed to stay on the Orbit 11 line. That gave a much better answer. Thanks!