Anti-matter Jump Drives?

[daltoncalford]

I am looking over pg 337 of the T5 final doc, and I am trying to figure out power requirements for an actual Jump.

ie - an IMTU version of the drives where Antimatter is used instead of fusion for jump drives.

Can someone who understands these things look to see if it is possible to figure out the EP required to perform a JX for hull Y from the material in T5?

 

[Reban]

Anti-Matter Power Plants are explicitly available to power the jump drive so technically it won't be IYTU it'll be high tech OTU.

You need to look at the Fuel Benchmarks chapter on p.361

Jump. The AM Power Plant processes fuel for the Jump Drive. The drive requires slugs equal to Jump Drive Potential times Hull tonnage divided by 10.

A fuel slug is processed from liquid hydrogen. A 100ton scout with J6 requires 60 slugs to be consumed by the JDrive.

 

[Original_Carl]

60 slugs? Better stock up on food for Nibbler.

 

[djwildstar]

I am looking over pg 337 of the T5 final doc, and I am trying to figure out power requirements for an actual Jump [...] Can someone who understands these things look to see if it is possible to figure out the EP required to perform a JX for hull Y from the material in T5?

Yes - the EP required for a Jump are the same regardless of what type of power plant you are using to power the drive. The quick rule of thumb is that a given Jump drive requires the EP produced by the matching power plant. The drive potential (and letter designator, if you are using pre-computed drives) of the power plant must match or exceed that of the jump drive. For example, if you you have a Jump Drive V (to make J-4 in a 1000-ton hull) you will need an Antimatter Power Plant V (which also has a drive potential of 4, and produces 2000 EP) to run it. You will also need fuel as described on page 339. For the example, you'll need 40 slugs/year for operations plus 400 slugs per jump. You can store 1000 slugs of antimatter per ton, so allocating 53 tons to fuel will provide for 5 years of operations and 132 Jump-4 (a jump every other week for 5 years) - "Space, the final frontier ..." ;-)

If you need more detailed information, the formula is on page 337: EP = (T-5)*20 where EP are the energy points required, and T is the tonnage of the Jump drive. The tonnage of the drive is also given, Jump = (H*J/200)*5+5. With a little bit of algebra, you can compute EP directly from hull tonnage and Jump number:
EP = ( [(H*J/200)*5+5] - 5) * 20
EP = [ (H*J/200)*5 ] * 20
EP = (H*J/200) * 100
EP = H*J/2