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Old March 9th, 2021, 10:55 AM
Garnfellow Garnfellow is offline
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Default Maintenance Crew for Mercenary Cruiser

I am really struggling to figure out how they ended up with 1 maintenance crew in the Imperial Encyclopedia.

The formula from the Consolidated Errata is Cm = (A C) 400 (drop fractions), where A=Hull displacement divided by 100 and C=Computer CP Multiple.

A Mercenary Cruiser is 800 tons displacement with 3 Model/5s, each of which has a CP Multiple of 35. No idea how to calculate CP with multiple computers, but let's ignore that for now.

800/100 = 8, divided by 35 = 0.2286, divided by 400 = .0006. Drop fractions = 0.

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