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Old May 22nd, 2019, 05:13 PM
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2. Choose locomotion/propulsion

Easy enough, that would be a Screw Propeller from the Vehicle Propulsion Types Table

So a Screw Propeller is TL 3, a Thrust type propulsion, takes up the normal number of spaces (x1) and has a reduced cost (x0.1).
But the table in the VDS stops way below anything close to the size of the TL 9 Destroyer or my Battleship. I guess it must be time to check back with the CE SRD and Starship Design. Fortunately, THRUST is THRUST, so the Base values should be the same and the specific modifiers for Propulsion type should still apply.

The table does not go to 12,000 tons but I can pretend that I have a fleet of 3000 ton hulls (x4) or a fleet of 4000 ton hulls (x3) that happen to be touching and calculate the total for all the drives (and later, the Power plants).
Drive K in an 800 ton hull gave the TL 9 Destroyer a performance of 3, so we will aim for that for our Battleship. We can adjust it later after we compare it to the speed of the historic ship.
That means a W drive in a 3000 ton hull for performance 3.
One Drive W is 41 tons and MCr 84, so four Drive W would be 164 tons (x12 = 1,968 spaces) and MCr 336 (x0.1 = MCr 33.6 ... for later).
Since the Destroyer added the Increased Agility option, we will add +1 agility to the Battleship as well.

Propulsion
  • Screw Propeller = - 1,968 spaces [x4 code W Ship Drives]
  • Increased Agility = - 0 spaces



3. Choose power supply

We select TL 5 Internal Combustion with increased spaces (x6), reduced cost (x0.05) and Hydrocarbon Fuel.
One Power Plant W is 64 tons and MCr 168, so four Power Plants (W) would be 256 tons (x6 x12 = 18,432 spaces) and MCr 672 (x0.05 = MCr 33.6 ... for later).

Power Plant
  • Internal Combustion = - 18,432 spaces [x4 code W Ship Drives]



4. Determine fuel requirements

The TL 9 Destroyer has a 672 hour (4 week) fuel capacity. Ironically, the Iowa Battleship had a range of 27,580 km at 28 kph (985 hours) and a top speed of 61 kph (<450 hours), so 4 weeks seems about right.
Hydrocarbons require more space than Hydrogen Fuel (x3) and each Power Plant W requires 84 tons of Hydrogen per 4 weeks.
So my 4 Power Plant W would need 336 tons of Hydrogen for 4 weeks, or 1008 tons (336x3) of Hydrocarbons.

1008 tons x 12 = 12,096 spaces of fuel (hydrocarbon)

Fuel
  • Hydrocarbon = - 12,096 spaces [672 hours]

Just a quick addendum: per the VDS, a performance 3 Screw Drive has a Base Speed of 60 KPH [as compared to the 61 kph Speed of the actual Iowa Class Battleships] ... well done Samardan Press! Clearly fractions of a G can be tweaked to match any real world ship if was important to the particular design.

Cruising speed is 75% of Base Speed = 45 kph with a duration of 1008 hours ... 45 kph x 1008 hrs = 45,360 km range.
I can reduce the fuel on the Battleship in half and use the spaces for more armor. Let's see how we are on space at the end before I start making changes.

Last edited by atpollard; May 22nd, 2019 at 08:16 PM..
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